What is the value assigned to the variable in each of these cases? Explain curious results. Be careful!

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What is the value assigned to the variable in each of these cases? Explain curious results. Be careful!

int x, y;
a) x = 1/2;
b) y = 3.0/2.0;
double z, w, t;
c) z = 1/2;
d) w = 3/2;
e) t = 3.0/2.0;

Answer:
a) 0 is assigned.1/2 is computed using truncating integer divide which gives 0.
b) 1.5 is calculated and assigned. The fractional part is discarded; 1 is stored.
c) 0 is calculated because 1/2 is done with truncating integer divide, gives 0. The floating point value 0.0 is stored.
d) 1 is calculated, because truncating int divide, 1.0 is stored
e) 1.5 is calculated and stored.

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